y(4y-3)=4(y^2+1)

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Solution for y(4y-3)=4(y^2+1) equation: 


Simplifying
y(4y + -3) = 4(y2 + 1)

Reorder the terms:
y(-3 + 4y) = 4(y2 + 1)
(-3 * y + 4y * y) = 4(y2 + 1)
(-3y + 4y2) = 4(y2 + 1)

Reorder the terms:
-3y + 4y2 = 4(1 + y2)
-3y + 4y2 = (1 * 4 + y2 * 4)
-3y + 4y2 = (4 + 4y2)

Add '-4y2' to each side of the equation.
-3y + 4y2 + -4y2 = 4 + 4y2 + -4y2

Combine like terms: 4y2 + -4y2 = 0
-3y + 0 = 4 + 4y2 + -4y2
-3y = 4 + 4y2 + -4y2

Combine like terms: 4y2 + -4y2 = 0
-3y = 4 + 0
-3y = 4

Solving
-3y = 4

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Divide each side by '-3'.
y = -1.333333333

Simplifying
y = -1.333333333

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